Given a binary tree, return the inorder traversal of its nodes' values.
For example:
Given binary tree
Given binary tree
[1,null,2,3]
,1 \ 2 / 3
return
[1,3,2].
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> inorderTraversal(TreeNode *root) {
vector<int> result;
inorderTra(root, result);
return result;
}
void inorderTra(TreeNode* node, vector<int> &result) {
if(node == NULL) {
return;
}
inorderTra(node->left, result);
result.push_back(node->val);
inorderTra(node->right, result);
}
};
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